Question

Usha swims in 9 long pool from one end to another and back.Here average velocity is​

Answer 1

Answer:

Explanation:

avg velocity=final displacement-initial displacement/change in time so

since usha is coming back to her original position to where she had started so avg velocity is 0

Answer 2

let the time taken by usha from one end to other = t

so distance total = 9 + 9 = 18m

average velocity = distance / time

average velocity = 9 - 9 / 2t = 0 /2t = 0

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