Question

usha swims in a 80 m pool she covers 160m in 2min by swimming from one end to other and back along the same straight path find the average velocity of usha​

Answer 1

Answer:

sorry I don't know the answer

Answer 2

Answer:

Distance = 180 m

Time = 1 min = 60sec

Average speed = total distance covered / total time taken

= 180m / 60 sec

= 3m/s

Displacement = 0m/s ( as usha come back along the same path so, the intial and final position is same )

Average velocity = displacement/ time

= 0m / 60 s

= 0m/s

Explanation: