Question

USHA SWIMS IN A 90 M LONG POOL. SHE COVERS 180 M IN 2 MINUTES BY SWIMMING FROM ONE END TO THE OTHER BACK ALONG THE STRAIGHT PATH. FIND DISPLACEMENT .
A . 180 M
B . 0 M
C . 90 M
D . 360 M​

Answer 1

Explanation:

Given,

Length of the pool = 90m

Time taken = 1m = 60sec (converted minute to second)

According to question, Usha travels from A to B, then back along the same straight path, B to A.

So, the total distance covered by Usha in 1 min = 90 + 90 = 180 m, and

the displacement of Usha in 1 min = 0 m (since she comes back to initial position)

Now, we know thats and her average velocity is 0 m/s.