Question

Usha swims in a 90 m long pool. She covers 180 m in one minute by swimming from one end to the
other and back along the same straight path. Find the average speed and average velocity of Usha.

Answer 1

Explanation:

Total Distance travelled=180m

total time taken=1min/60seconds

average speed=Distance travelled/time taken

=180/60

=3m/s

Displacement=90m

total time taken=180s

average velocity=displacement/time taken

=90/180

=0.5m/s

Answer 2

$\huge\mathfrak\pink{Solution}$

Total distance covered by Usha in 1 min is 180 m..

Displacement of Usha in 1 min = 0 m..

${ \ Average \ speed}$ $\tt{\implies}$$\frac{Total \ distance \ covered}{Total \ time \ taken}$

$\frac{180m}{1min}$ ${ \ =}$ $\frac{180m}{1min}$ ${ \ ×}$ $\frac{1min}{60s}$

$\tt{\implies}$ ${ \ 3m s¯¹}$

${ \ Average \ velocity}$ $\tt{\implies}$ $\frac{Displacement}{Total \ time \ taken}$

$\tt{\implies}$ $\frac{0m}{60s}$

$\tt{\implies}$ ${ \ 0 m s¯¹}$

$<font color=red>$ The average speed of Usha is 3m s¯¹ and her average velocity is 0 m s¯¹

$\huge\mathfrak\pink{hope \ it's \ helps \ you}$