Question

Usha swims in a 90 m long pool. She covers 180 m in one minute going either way. The
average velocity is:​

Answer 1

$\huge\underline\bold{Solution}$

➝ Total distance covered in 1 min = 180m.

➝Displacement in 1 min = 0m

$\:\sf\underline\red{Average\:velocity}\:$

⠀⠀⠀⠀⠀⠀⠀= $\dfrac{Displacement}{Total\:time\:taken}$

⠀⠀⠀⠀⠀⠀⠀= $\dfrac{0m}{60s}$

⠀⠀⠀⠀⠀⠀⠀= 0m ${s}^{-1}$

The average velocity is 0m ${s}^{-1}$