Question

Usha swims in a 90 m long pool.She covers 180 m in one minute by swimming from one end to the other and back along the same straight path.Find the average speed and average velocity of Usha.

Answer 1

this is the answer of your question

Answer 2

$\blue{Speed = {\frac{Distance}{Time}}}$

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GIVEN

«Distance = 180m

«Time = 1min = 60s

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Speed = $\frac{180}{60}$ = 3m/s

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Displacement is the actual distance moved. So she came back to the actual position. Hence, displacement = 0

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$\orange{Velocity={\frac{Displacement}{Time}}}$

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GIVEN:-

Displacement = 0m

Time = 1 min = 60s

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Velocity = $\frac{0}{60}$ = 0 m/s