Usha swims in a 90 m long pool. She covers 180m in one minute by swimming from one end to the other and back along same straight path. Find average speed and velocity?
Answers
Answer:
average velocity = 0
as avg vel = displacement/time
Explanation:
avg speed = total dist/total time
1min = 60 sec
avg speed= 180/60
avg speed = 3m/s
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Usha swims in a 90 m long pool. She covers 180m in 1 minute (1 min = 60 sec) by swimming from one end to the other and back along same straight path
We have to find the average speed and average velocity of Usha.
Average speed is defined as the total distance covered with respect to total time taken. Whereas average velocity is defined as the ratio of total displacement with respect to the total time taken.
As given in question that, the Usha covers a distance of 180 m in 60 sec.
(Total distance covered is 180 m and time taken is 60 sec).
Average speed = 180/60 = 3 m/s
Therefore, the average speed of the Usha is 3 m/s.
Since, she is swimming from one end to the other and back along the same straight path. So, the total displacement of the Usha is zero.
Therefore, the average velocity of the Usha is 0 m/s.