Physics, asked by mufiahmotors, 1 month ago

usha swims in a 90 m long pool. she covers 180m in one minute by swimming from one end to the other and back along the same straight path find speed and average velocity of usha.​

Answers

Answered by gokulsanjayreddy
1

Answer:

Here's the correct answer

Explanation:

Length of the pool: 90m

Average speed:

Speed= Distance/Time

speed=180/60

speed=30 m/s

Velocity:

velocity=displacement/time

displacement=0( Since she comes back to the same place)

velocity=0

Hope you can get it..

Answered by ITZURADITYAKING
1

Answer:

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Explanation:

Distance = 180 m

Time = 1 min = 60sec

Average speed = total distance covered / total time taken

= 180m / 60 sec

= 3m/s

Displacement = Om/s (as usha come back along the same path so, the intial and final position is same)

Average velocity = displacement/ time

= Om / 60 s

= Om/s

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