Question

usha swims in a 90 m long pool. she covers 180m in one minute by swimming from one end to the other and back along the same straight path find speed and average velocity of usha.​

Answer 1

Answer:

Given,

Length of the pool = 90m

Time taken = 1m = 60sec (converted minute to second)

According to question, Usha travels from A to B, then back along the same straight path, B to A.

So, the total distance covered by Usha in 1 min = 90 + 90 = 180 m, and

the displacement of Usha in 1 min = 0 m (since she comes back to initial position)

Now, we know that-

Hence, the average speed of Usha is 3 m/s and her average velocity is 0 m/s.

Answer 2

Answer:

→ Hey Mate ,

→ Given Question : usha swims in a 90 m long pool. she covers 180m in one minute by swimming from one end to the other and back along the same straight path find speed and average velocity of usha.​

Explanation:

→ Usha swims in a 90 m long pool .  ( Given in Question )

→ Total Distance = 180 m

→ Time Taken = 60s

→ Average speed = Total Distance / time taken

→                            =  $\frac{180}{60} = 3ms^-^1$

→ Displacement  = 0

→ Average velocity = Displacement / Time

→                              =  0 / 60 = 0ms^-1

thank you ,

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