Question

Usha swims in a 90m long pool from one end to another and back in 5s. What is her

average velocity?​

Answer 1

Explanation:

∆v= ∆x/∆t

here, x1 = 0m ; x2= 90m

t1= 0 sec ; t2 = 5 sec

putting these values in the above formula ; we get

v = 90-0\5-0 = 90/5 = 18m/s