Physics, asked by karanpillai, 1 month ago

Usha swims in a 90M long pool she covers 180 meters in one minute by swimming from one end to the other and back along the same path find the average speed and average velocity of usha​

Answers

Answered by prachi171106
4

Answer:

speed= 3m/s and velocity = 0m/s

Explanation:

Length of the pool = 90m

Time taken = 1m = 60sec (converted minute to second)

According to question, Usha travels from A to B, then back along the same straight path, B to A.

So, the total distance covered by Usha in 1 min = 90 + 90 = 180 m, and

the displacement of Usha in 1 min = 0 m (since she comes back to initial position)

Now, we know that-

Average Speed=Total distance travelled/Total time taken

                            =180/60

                            =3m/s ans.

average velocity= total displacement/ total time taken

=0/60

=0m/s ans.

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