Usha swims in a 90m long pool. She covers 180m in one minute by swimming from one end to the other and back along the same straight path. Find the average speed & average velocity of usha.
No spam pls
Answers
Answered by
6
Answer:
Distance = 180 m =
Time = 1 min = 60 sec
Average speed = total distance covered / total time taken
= 180m / 60 sec
= 3m/s
Displacement = On/s ( as usha come back along the same path so, the intial and final position is same )
Average velocity = displacement/
time
= Om / 60 s
= Om/s
KYA YRR ITNA ASSAN THA
CHAL ABB SOO JA
GOOD NIGHT CUTIE
Answered by
2
Answer:
Average speed=3m/s-¹
Average velocity=0m/s-¹
Explanation:
Total distance covered by Usha in 1 min is 180 m
displacement of Usha in 1 min=0 m
Average speed=total distance covered÷ total time taken
=180m÷1 min=180m÷1 min×1min ÷ 60 s
=3m/s-¹
Average velocity=Displacement÷total time taken
=0m÷60 s
=0 m/s-¹
Similar questions