Question

Usha swims in a90m long.She covers 180m in one mine minute by swimming from one end to the other and back along the same straight path . find the average and speed velocity of Usha
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Answer 1

Distance = 180 m

Time = 1 min = 60sec

Average speed = total distance covered / total time taken

= 180m / 60 sec

= 3m/s

Displacement = 0m/s ( as usha come back along the same path so, the intial and final position is same )

Average velocity = displacement/ time

= 0m / 60 s  

= 0m/s

HOPE IT HELPS.