Question

Usha swims Usha swims in our 90 metre long cool covers 180 metre in 1 minute by swimming from one end to the other and back along the same straight path per find the average speed and average velocity of USha

Answer 1

Answer:

0m/s

Explanation:

Distance = 180 m

Time = 1 min = 60sec

Average speed = total distance covered / total time taken

= 180m / 60 sec

= 3m/s

Displacement = 0m/s ( as usha come back along the same path so, the intial and final position is same )

Average velocity = displacement/ time

= 0m / 60 s

= 0m/s

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Answer 2

Answer:

Distance=3m/s Displacement=0 m/s

Explanation:

i)Average speed -

total distance covered = 180m

total time taken = 60 sec

average speed = total distance/ total time = 180/60

= 3m/s

ii)Average velocity

total displacement = initial point - final point = 0m/s

total time taken = 60m/s

average velocity = total displacement/ total time

= 0m/s / 60m/s

= 0m/s

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