Question

. Usha swings in a 100m long pool from one end to another and back. what is her average velocity? *​

Answer 1

Distance = 200m

Time = 1 min = 60sec

Average speed = total distance covered / total time taken

= 200m / 60 sec

= 3.33 m/s

Displacement = Om/s (as usha come back along the same path so, the intial and final position is same)

displacement final position - initial position

= 100 -100 = 0m

Average velocity displacement/ time =

= Om / 60 s

= 0m/s

Brainlist please...