Question

usimg a horizontal force of 200N, we intend to move a wooden cabinet across a floor at at a constant velocity. what is the friction force that will be exerted on the cabinet?​

Answer 1

Answer:

As the velocity of the cabinet is constant, its acceleration ought to be zero. Therefore, the active force acting on it is also zero. This implies that the magnitude of opposing frictional force is equal to the force exerted on the cabinet, which is 200 N. Therefore, the total friction force is -200 N.

Answer 2

Explanation:

because the friction attract