Question

usin
a compound interest on
6000 for 2 years at 9% per annum compounded annually
nually
* 100 for 2 years at 11% per annum compounded annually​

Answer 1

Answer:

CI = 1128.6

Step-by-step explanation:

Amount = P ( 1 + R / 100 )^TP(1+R/100)T

Given :

Principal = Rs. 6000

Time Period = 2 years

Rate of interest = 9%

Substituting in the formula we get,

=> Amount = 6000 ( 1 + 9 / 100 )²

=> Amount = 6000 ( 1 + 0.09 )²

=> Amount = 6000 ( 1.09 )²

=> Amount = 6000 ( 1.1881 )

=> Amount = 7128.60

Hence the amount is Rs. 7128.60

Compound Interest = Amount - Principal

=> CI = 7128.6 - 6000.0

=> CI = 1128.6

Hence it is the required answer.

Answer 2

Answer:

$:\implies\sf Amount = P \bigg\lgroup 1 + \dfrac{R}{100}\bigg\rgroup^{n}$

$:\implies\sf Amount = 6000 + \bigg\lgroup 1 + \dfrac{9}{100}\bigg\rgroup^2$

$:\implies\sf Amount = 6000 \big\lgroup 1 + 0.09\big\rgroup^2$

$:\implies\sf Amount = 6000 \big\lgroup 1.09\big\rgroup^2$

$:\implies\sf Amount = 6000 \big\lgroup 1.1881\big\rgroup$

$:\implies \underline{ \boxed{\sf Amount =Rs. \: 7128.60 }}$

$\therefore\:\underline{\textsf{The Amount is \textbf{Rs. 7128.60}}}.$

________________________

⠀

$\dashrightarrow\:\:\sf Compound \: Interest = Amount - Principal$

$\dashrightarrow\:\:\sf Compound \: Interest = 71286.60 - 6000$

$\dashrightarrow\:\:\underline{\boxed{\sf Compound \: Interest = 1128.6}}$

$\therefore\:\underline{\textsf{The Compound Interest is \textbf{Rs. 112.86}}}.$