using 2 law of motion drive relation b/w force and accleration
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Answered by
1
According to second law of motion
F=change in momentum per unit time
F=∆p/∆t…………………(1)
As we know p=mv
So change in momentum (∆p)=∆(mv)
∆p=m∆v.................... (2)
(since mass is constant and only velocity changes)
Also acceleration a=change in velocity per unit time
a=∆v/∆t…………………(3)
Using (1)&(2)
F=m∆v/∆t
Using (3)
F=ma
This is the relation between force and acceleration which you are looking.
F=change in momentum per unit time
F=∆p/∆t…………………(1)
As we know p=mv
So change in momentum (∆p)=∆(mv)
∆p=m∆v.................... (2)
(since mass is constant and only velocity changes)
Also acceleration a=change in velocity per unit time
a=∆v/∆t…………………(3)
Using (1)&(2)
F=m∆v/∆t
Using (3)
F=ma
This is the relation between force and acceleration which you are looking.
Answered by
1
Consider a body of mass ‘m’ moving with velocity v.
The linear momentum of a body is given by:
p = mv
Now According to Newton’s 2nd Law of Motion:
Force is directly proportional to rate of change of momnetum, that is
F α dp/dt
F = k dp/dt
F = k d(mv)/dt
F = k md(v)/dt
F = k ma
Experimentally k =1
F = k ma
Which is the required equation of force.
kaushiksneha273:
easy to understand
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