using 5^2 +6^2 = 61 draw a segment of length √61 cm
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Given:
5^2 +6^2 = 61
To find:
To draw a segment of length √61 cm
Solution:
Consider the attached figure, while going through the following steps.
Since given is a Pythagorean triplet, we have, 5² + 6² = (√61)²
Draw a line AB with a scale of 5 cm.
From point B draw a perpendicular line of length 6 cm.
Mark the other point as C.
Join AC.
Hence the required segment AC of length √61 cm.
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