Question

using 5²+6²=61 draw a segment of length √61 cm
Plz Explain also
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Answer 1

Answer:

$\huge \underline\mathbf \red{Answer}$

Given:

${5}^{2} + {6}^{2} = 61$

To find:

To draw a segment of length √61cm

Solution:

consider the attached figure,while going through the following steps.

since given is a Pythagorean triplet,we have, 5^2+6^2=(√61)^2

Draw a line AB with a scale of 5cm.

From point B draw a perpendicular line of length 6cm

Mark the other point as C.

join AC.

Hence the required segment AC of length √61cm.