Question

using a^2-b^2=(a+b)(a+b) ,find (1.02)^2-(0.98)^2
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Answer 1

Answer:

(1.02)

2

−(0.98)

2

Using,

a

2

−b

2

=(a+b)(a−b) we get,

=(1.02+0.98)(1.02−0.98)

=2×0.04

=0.08

Step-by-step explanation:

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Answer 2

$\huge \bold \color{green}{ \underline{ \underline \red{required \: answer : }}}$

we have to find value of (1.02)²-(0.98)²

$\bold{by \: using \: {a}^{2} - {b}^{2} = (a + b)(a - b) }$

so..

$\bold{{(1.02)}^{2}-{(0.98)}^{2} = (1.02 + 0.98)(1.02 - 0.98) }$

$\implies2 \times 0.04 \\ \implies0.08$

so (1.02)²-(0.98)² = 0.08