Question

using (a+b)) 2=a +b2+ab evaluate (137)2

Answer 1

■ GIVEN THAT ;-

$(a + b)^{2} = {a}^{2} + {b}^{2} + 2ab$

■ SOLUTION:-

$(130 + 7)^{2} = ( {130})^{2} + ( {7})^{2} + 2 \times 130 \times 7$

$16,900 + 49 + 1,820$

$18,769$

hope it helps you

Answer 2

Step-by-step explanation:

$using \: the \: formula\\ ( {a + b})^{2} = {a}^{2} + {b}^{2} + 2ab \\ (137) {}^{2} \\ = (130 + 7) {}^{2} \\ = {130}^{2} + {7}^{2} + 2(130)(7) \\ = 16900 + 49 + 1820 \\ = 18769$

here you go if you are satisfied with my answer thank me