using a graph demonstrate a function which is one-one but not onto
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TO DETERMINE
using a graph demonstrate a function which is one-one but not onto
EVALUATION
We know that for two non empty sets A and B a mapping f from A to B is a rule that assigns to each element x of A a definite element y in B
A mapping f : A B is said to be one to one if x ≠ x' implies f(x) = f(x')
Again f is said to be onto if each element y of B has at least one preimage
Let us consider the sets
A = { 1 , 2 , 3 } and B = { a , b , c , d }
Define mapping f : A B such that
f(1) = b , f(2) = a , f(3) = d
Then f is one to one
But the element c in the codomain set B has no preimage
So f is not onto
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f ( x ) =
Explanation:
in an 'onto' function, every x -value is mapped to a y − value.
in a one-to-one function, every y -value is mapped to at most one x - value.
this means that in a one-to-one function, not every x -value in the domain must be mapped on the graph. it only means that no y -value can be mapped twice.
the graph of is one-to-one. there is no more than one x -value for each y -value, and there is no more than one y -value for each x-value.
this can be shown using the horizontal line test: a horizontal line, drawn anywhere on the graph (i.e. of any y -value), will not intersect with a one-to-one function more than once (if at all).
the graph of not every y -value is mapped on the graph;
can never be 0 or below. y = 0 is the horizontal asymptote of the graph.