Question

using a horizontal force of 200 Newton we intend to move a wooden cabinet across a floor at a constant velocity what is the friction force that will be exerted on the cabinet​

Answer 1

Hey mate,,

Force = Mass x Acceleration

For constant velocity, the net external force acting on the system should be zero.

In the vertical direction, it's weight will cancel out the normal reaction force.

In the horizontal direction, similarly, the frictional force has to cancel the applied force of 200 N. In order to do that, the frictional force should be of the same magnitude as the applied force and in a direction exactly opposite to that of the applied force.

Hence, the magnitude of the frictional force should be 200 N, and it's direction should be opposite to that of the applied force.

Answer 2

Answer:

Since the wooden cabinet is to be moved at constant velocity, this means that the whole force of 200 N will be used to overcome the force of friction. Thus, the force of friction exerted on the cabinet will be equal to the force applied, which is 200 N.