using a horizontal force of 200N, we intend to move a wooden cabinate across a floor at a constant velocity. What is the friction force that will be exerted on the cabinet
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Using a horizontal force of 200 N, we intend to move a wooden cabinet across a floor at a constant velocity. ... Therefore, force of friction on the cabinet = 200 N, in a direction opposite to the direction of motion of the cabinet.
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For an object to move with constant velocity, net external force experienced by it must be equal to ZERO i.e Fexternal=0
Thus a friction of 200 N must be exerted on the cabinet so that it moves with a constant velocity under the applied horizontal force of 200 N.
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