Question

Using a long division method, show that (z^2+3) = (z^5-9z)​

Answer 1

z2 + 3 is a factor of z5 – 9z Firstly let us perform long division method Since the remainder is 0, z2 + 3 is a factor of z5 – 9z.Read more on Sarthaks.com - https://www.sarthaks.com/663860/using-division-of-polynomials-state-whether-z-2-3-is-a-factor-of-z-5-9z