Using a pair of compass and ruler. Construct triangle PQR in which
QR = 5.5 cm Q = 60° and PQ + PR = 9.5 cm.
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Steps of Construction :
(1) Draw a line PQ = 5.5 cm.
(2) From Q as a centre draw an arc QR = 7.5 cm.
(3) From P as a centre draw an arc PR = 6 m, which intersects previous arc at R.
(4) Join PR and QR.
(5) Now, draw interior bisectors of ∠P, ∠QR ∠R which meets each other at point S.
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