Question

Using a pair of compass and ruler, construct triangle PQR in which QR=5cm ,angle Q=75degree and PQ+PR=8cm​

Answer 1

Step-by-step explanation:

Let a number of notes are 2x, 3x and 5x.

According to question, 100 x 2x + 50 x 3x + 10 x 5x =4,00,000

\Rightarrow\ 200x+150x+50x=4,00,000⇒ 200x+150x+50x=4,00,000

\Rightarrow\ 400x=4,00,000⇒ 400x=4,00,000

\Rightarrow\ \frac{400x}{400}=\frac{400000}{400}⇒

400

400x

=

400

400000

[Dividing both sides by 400]

x = 1000

Hence, number of denominations of ` 100 notes = 2 x 1000 = 2000

Number of denominations of ` 50 notes = 3 x 1000 = 3000

Number of denominations of ` 10 notes = 5 x 1000 = 5000

Therefore, required denominations of notes of 100, 50 and ` 10 are 2000, 3000 and 5000 respectively.

Answer 2

Answer:

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Step-by-step explanation:

1. Draw a line PQ = 5.5 cm

2. From Q as a center draw an arc QR = 7.5 cm

3.From P as a center draw an arc PR - 6 cm

4.Join PR and QR

5.Draw a line PQ = 5.5 cm

6.From Q as a center draw an arc QR = 7.5 cm

7.From P as a center draw an arc PR - 6 cm

8.Join PR and QR

9. Now draw interior bisectors of \angleP, \angleQ and \angleR which meets each other at point S.