Question

using a pattern show that the difference between the two consecutive square number will always be an odd number​

Answer 1

Answer:

To Prove : Difference between the two consecutive square number will always be an odd number​

Proof :

Let there be 2 consecutive numbers x and x+1

So,

difference of their squares=>

$(x + 1)^2 - x^2$

=> $x^2 + 1 + 2x - x^2$

=> 2x + 1

Now, we can see that in 2x + 1, 2x will always be an even number. Adding 1 to an even number gives us an odd number.

Hence, Difference between the two consecutive square number will always be an odd number​  

* note: 2 consecutive numbers‘ square is 2 consecutive square numbers.*

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Answer 2

Answer:

Step-by-step explanation:

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