Question

Using a ruler draw any triangle ABC . Measure the sides AB, BC and CA . Show that the sum of any two sides is greater than the third side . [Hint: Show AB + BC> CA, BC + CA > AB and AB + CA > BC .]
$ans$
​

Answer 1

If A and B be any two 3 3 matrices. If A is symmetric and B is skew symmetric then the

matrix AB – BA is

Answer 2

Answer:

Step-by-step explanation:

In ΔABC if we take the length of AB=3cm BC=4cm CA=5cm AB+BC>CA (3cm+4cm>5cm)=(7cm>5cm).  BC+CA>AB (4cm+5cm>3cm)=(9cm>3cm)                AB+CA>BC  (3cm+5cm>4cm)=(8cm>4cm).Thus it is proved.