using a suitable identity evaluate (-28)cube+(9)cube+(19)cube
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Let a=-28 , b=9 , c=19 , a+b+c=0
We know , a³+b³+c³ = 3abc if (a+b+c)=0
Hence (-28)³+9³+19³ = 3(-28)(9)(19)
= -14364
We know , a³+b³+c³ = 3abc if (a+b+c)=0
Hence (-28)³+9³+19³ = 3(-28)(9)(19)
= -14364
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0
Answer:
Use suitable identities to find the following products: (i) (x + 4) ... x2 +(8-10)x - 80 ... (-2x )2 + (3y)2 + (2z)2 + 2(-2x)(3y) + 2(3y)(2z) + 2(2z)(-2x) ... Q6: Write the following cubes in
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