Question

using a²-b²=(a+b) (a-b) find

1) 153²-147²​

Answer 1

Answer:

1800

Step-by-step explanation:

${a}^{2} - {b}^{2} = (a + b)(a - b)$

${153}^{2} - 14 {7}^{2} = (153 + 147)(153 - 147)$

$15 {3}^{2} - 147 ^{2} =( 300)(6)$

$15 {3}^{2} - 147 ^{2} = 300 \times 6$

$153 ^{2} - 147 ^{2} = 1800$

Answer 2

Given: a²-b²=(a+b) (a-b)

To find  The value of 153²-147²​ using a²-b²=(a+b) (a-b)

Solution: The replacement of numbers into letters in mathematics, is done by the branch called algebra. The formulas which are found from the expressions of algebra are called algebraic formulas. The numbers in algebraic expressions are considered to be constant. We use algebra in our daily lives when we do astrological calculations.

Now from above-using a²-b²=(a+b) (a-b) to find the value of 153²-147²​, we have

153²-147²  [ form: a²-b²]

=(153+147)×(153-147)  [form: (a+b) (a-b)]

=300×6

=1800

Hence the value of 153²-147²​ using a²-b²=(a+b) (a-b) is 1800.