Using algebraic identities (3 + 4 b) square
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Answered by
0
Answer:
3^2+(4b)^2+2×3×4b
=9+16b^2+24b
Answered by
0
Answer:
9+24b+16b^2
Step-by-step explanation:
this is the identity (a+b)^2= (a^2)+2(a)(b)+(b^2)
here a=3 and b =4b
so,
(3)^2+2x(3)x(4b)+(4b)^2
=9+24b+16b^2
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