Question

using algebraic identity 173×173×173+127×127+127 /173×173-173×127+127×127

Answer 1

      (173)³ + (127)³        

(173)² - 173 x 127 + (127)²

=   (173 + 127) (173²   - 173 x 127 +  127²)           [a³+ b³ = (a+b)(a² - ab + b²)]

        173² - 173x 127 + 127²

= 173 + 127 = 400

Answer 2

Answer:

300

Step-by-step explanation:

Given expression,

$\frac{173\times 173\times 173 + 127\times 127\times 127}{173\times 173-173\times 127+127\times 127}$

$=\frac{173^2+127^3}{173^2-173\times 127+127^2}$

We know that,

a³ + b³ = ( a + b ) ( a² - ab + b² )

$=\frac{(173+127)(173^2-173\times 127+127^2)}{173^2-173\times 127+127^2}$

$=173 + 127$

= 300