Question

using algebric expression identity iv) x - 16​

Answer 1

it will be x-16 only....

Answer 2

Step-by-step explanation:

$x - 16 = 0 \\ (\sqrt{x} + 4)( \sqrt{x } - 4 ) = 0 \\ \sqrt{x } + 4 = 0 \: \: \: or \: \: \sqrt{x} - 4 = 0 \\ \sqrt{x } = - 4 \: \: \: or \: \: \: \sqrt{x} = 4 \\ negetive \: roots \: are \: not \: posible \: \\ so \: \sqrt{x} = 4 \\ x = (4) ^{2} \\ x = 16$

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