Question

Using algebric formula ,find the value of 64x^(3)+144x^(2)+108x+30 ,when x= 1/4​

Answer 1

Answer:

64x3+144x^2+108x+27

Final result :

(4x + 3)^3

Step by step solution :

Step 1 :

Equation at the end of step 1 :

(((64 • (x^3)) + (2^4•3^2x^2)) + 108x) + 27

Step 2 :

Equation at the end of step 2 :

((2^6x^3 + (2^4•3^2x2)) + 108x) + 27

Step 3 :

Checking for a perfect cube :

3.1 Factoring: 64x^3+144x^2+108x+27

64x^3+144x^2+108x+27 is a perfect cube which means it is the cube of another polynomial

In our case, the cubic root of 64x^3+144x^2+108x+27 is 4x+3

Factorization is (4x+3)^3

Final result :

(4x + 3)^3

❤️

Answer 2

$\bold\pink{ANSWER:}$

Given,

$\bold\purple{x=1/4}$

$\bold\green{=>64x^(3)+144x^(2)+108x+30}$

$\bold\green{=>64(1/4)^3+144(1/4)^2+108(1/4)+30}$

$\bold\green{=>64(1/64)+144(1/16)+27+30}$

$\bold\green{=>1+18/2+27+30}$

$\bold\green{=>58+9}$

$\bold\green{=>67}$

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