using ampere circuital low find the magnetic flux density at the centre of long solenoid carrying current.
Answers
Answer:
Consider a long straight conductor carrying current I perpendicular to the page in upward direction as shown below in the figure
Proof Of Ampere's Law
From Biot Savart law, the magnetic field at any point P which is at a distance R from the conductor is given by
Direction of magnetic Field at point P is along the tangent to the circle of radius R withTh conductor at the center of the circle
For every point on the circle magnetic field has same magnitude as given by
And field is tangent to the circle at each point
The line integral of B around the circle is
since ∫dl=2πR ie, circumference of the circle so,
This is the same result as stated by Ampere law
This ampere's law is true for any assembly of currents and for any closed curve though we have proved the result using a circular Amperean loop
If the wire lies outside the amperion loop, the line integral of the field of that wire will be zero
but does not necessarily mean that B=0 everywhere along the path ,but only that no current is linked by the path
while choosing the path for integration ,we must keep in mind that point at which field is to be determined must lie on the path and the path must have enough symmetry so that the integral can be evaluated
Explanation: