Using an appropriate expansion,find the cube of each of the following 4a2-3b
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Step-by-step explanation:
We need to expand (2a−3b)
3
We know suitable identity is (x−y)
3
=x
3
−3x
2
y+3xy
2
+y
3
Here x=2a and y=3b
Therefore, value of (2a−3b)
3
is
=(2a)
3
−3(2a)
2
(3b)+3(2a)(3b)
2
−(3b)
3
=8a
3
−36a
2
b+54ab
2
−27b
3
I hope this answer is helpful for you
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