Question

Using an engine of 30% thermal efficiency to drive a refrigerator having
a COP of 5, what is the heat input into the engine for each MJ removed
from the cold body by the refrigerator?

Answer 1

Answer:

A heat engine with 30% efficiency drives a refrigerator of COP 5.0. ... Thus, the net heat input to the engine for each megawatt of heat removed from in the refrigerator is 6.6 megawatt.

Explanation:

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