Question

using analyatical method obtained an expression for the path difference between two light waves​

Answer 1

Answer:

Explanation:

a) Let S1 and S2 be the two coherent monochromatic sources which are separated by short distance d. They emit light waves of wavelength λ

b) Let D = horizontal distance between screen and source

c) Draw S1M and S2N ⊥ AB

OP = perpendicular bisector of slit.

Since S1P = S2P, the path difference between waves reaching P from S1 and S2 is zero, therefore there is a bright point at P.

d) Consider a point Q on the screen which is at a distance x from the central point P on the screen. Light waves from S1 and S2 reach at Q simultaneously by covering path S1Q and S2Q, where they superimpose

h).  If x << D and d << D then,

S1Q ≈ S2Q ≈ D

S2Q + S1Q = 2D

∴ Equation (3) becomes,

 

S2Q-S1Q=2xd2D

 

∴△x=xdD                .........4

Equation (4) gives the path difference of two interfering light waves

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