Question

Using ∝and β, find the equation in the forum ax2+bx + c = 0 whose ums and products are respectively

(a)32, -52

b. 1.2,0.8
c. -5,6​

Answer 1

Answer:

Please write in proper way but I understood something .

Step-by-step explanation:

sum is alpha plus Beeta equal to -b/a

product is alpha*Beeta equal to c/a

Answer 2

SOLUTION

GIVEN

Using α and β, find the equation in the forum ax² +bx + c = 0 whose sum and products are respectively

a. 32, -52

b. 1.2,0.8

c. -5,6

CONCEPT TO BE IMPLEMENTED

If the Sum of zeroes and Product of the zeroes of a quadratic equation are given then the quadratic equation is

$\sf{ {x}^{2} -(Sum \: of \: the \: zeroes )x + Product \: of \: the \: zeroes } = 0$

$\sf{If \: \alpha \: \: and \: \: \beta \: are \: the \: zeroes }$

Then the equation is

$\sf{ {x}^{2} - ( \alpha + \beta )x + \alpha \beta = 0}$

(i)

Here

$\sf{ ( \alpha + \beta ) = 32 \: \: and \: \: \alpha \beta = - 52}$

So the quadratic equation is

$\sf{ {x}^{2} - 32x - 52 = 0}$

(ii) Here

$\sf{ ( \alpha + \beta ) = 1.2 \: \: and \: \: \alpha \beta = 0.8}$

So the quadratic equation is

$\sf{ {x}^{2} -1.2x + 0.8= 0}$

(ii)

Here

$\sf{ ( \alpha + \beta ) = - 5 \: \: and \: \: \alpha \beta = 6}$

So the quadratic equation is

$\sf{ {x}^{2} + 5x + 6= 0}$

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