Question

Using appropirate identity solve

(-32)^3+(18)^3+(14)^3

Answer 1

if
$a + b + c = 0$
then,
${a}^{3} + {b}^{3} + {c}^{3} = 3abc$
$( - 32) + 18 + 14 = 0$
${( - 32)}^{3} + {18}^{3} + {14}^{3} = 3( - 32)(18)(14) \\ = 8064$
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