Math, asked by mandarbandre, 9 months ago

using appropriate identify factorize 9xsq +6x +1

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Answered by niharika0710

1

hey

checkout attached photo

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Answered by Lucy0001

1

Answer:

${9x}^{2} + 6x + 1 \\ = > {(3x)}^{2} + 2 \times 3x \times 1 + {(1)}^{2} \\ = {(3x + 1)}^{2}$

using identity (a+b)^2=a^2 + 2ab + b^2

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