Using appropriate method, approximate the value of ln(2).
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ln(2) = loge(2) = 0.6931.
ln(3) = loge(3) = 1.0986.
ln(4) = loge(4) = 1.3862.
ln(5) = loge(5) = 1.609.
ln(6) = loge(6) = 1.7917.
ln(10) = loge(10) = 2.3025.
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