Math, asked by Tithi16786, 1 year ago

using appropriate properties find (2/3)×(-5/7)+(7/3)+(2/3)×(-2/7)​

Answers

Answered by SaurabhJacob
8

Given:

(2/3)×(-5/7)+(7/3)+(2/3)×(-2/7)​

To Find:

Solve (2/3)×(-5/7)+(7/3)+(2/3)×(-2/7)​ using appropriate properties

Solution:

We will use the distributive property to solve the given problem

According to the distributive property

a(b+c) = ab + ac

Now,

(2/3)×(-5/7)+(7/3)+(2/3)×(-2/7)​

We will take 2/3 as common

=2/3((-5/7-2/7))+7/3

=(2/3)((-5-2)/7) +7/3    [When denominator is same then numerator gets

                                    add]

= 2/3(-7/7)+7/3          [-7/7 = -1]

=2/3(-1)+7/3          

=-2/3 + 7/3                 [When denominator is same then numerator gets

                                    add]

= (-2+7)/3

= 5/3

Hence, the answer is 5/3.

Answered by videeshvan5
0

Answer:

5/3

Step-by-step explanation:

According to the distributive property

= (2/3 × -5/7) + (2/3 × -2/7) + 7/3

= 2/3(-5/7 - 2/7) + 7/3

= 2/3(-7/7) + 7/3

= -2/3 + 7/3

=5/3

i hope this would help you!

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