using approximation method approximate (255)^1/3
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(255^1/3)=(6^3+39)^1/3=6(1+39/216)^1/3 =6(1+(1/3)*(39/216))=6(1+13/216)=6•36
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Answer:
Step-by-step explanation:
del y= f(x+del x) - f(x)
here (255)^1/3=f(x+ del x)
dy/dx=del y/ del x
from above del y= dy/dx * del x
suppose you have y=x^1/3
then dy/dx=1/3 x^-2/3
here x=216 because it is the nearest perfect cube
therefore= dy/dx=1/3(216)-2/3
dy/dx=1/3(1/216)^2/3)
dy/dx=1/3(1/36)=1/108
del y=dy/dx * del x
=1/108*(255-216)
=1/108*36
=0.36
therefore f(x+ del x)=255^1/3=0.36+6
=6.36
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