Question

using babylonian procedures, solve the system x-y=4, xy=21

Answer 1

Answer:

X= 7 y= 3

Step-by-step explanations

X= 4+y

put value of X in xy = 21

(4+y)y=21

y^2+4y -21= 0

y^2+7y-3y-21=0

y(y+7)-3(y+7)=0

(y-3)=0 (y+7)=0

y=3. or. y= -7