Question

Using bearing scale drawing. A girl walks 40m north and 150m east. How far is she from her starting position

Answer 1

Answer:

155.241m

Step-by-step explanation:

It forms a right angled triangle

Hypotenuse^2=40^2+150^2

Hypotenuse^2=1600+22500

Hypotenuse^2=24,100

Hypotenuse =155.241

She is 155.241 m far from her starting position

Answer 2

Answer:

155.25 metres.

Step-by-step explanation:

Let the girl started from point A and walks 40 m north. At point O, she turns towards east and walks 150 m east upto point B.

[Refer to the attachment for picture]

To find :

• The displacement of the girl, i.e., shortest distance possible from her initial position to final position.

In ΔAOB, ∠O = 90°.

By using Pythagoras formula :

AB² = AO² + BO²

⇒ AB² = (40)² + (150)²

⇒ AB² = 1600 + 22500

⇒ AB² = 24100

⇒ AB = ±√24100

⇒ AB = ± 155.241..

Taking the positive value, AB = 155.25 metres.

Hence, she is 155.25 m away from starting point.