Using binomial theorem , find (1-2x)^5
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Answer:
1 - 10x + 40x² - 80x³ + 80x^4 - 32x^5
Step-by-step explanation:
(1-2x)^5 = 1 - 5(1×2x) + 10{1×(2x)²} - 10{1×(2x)³} + 5{1× (2x)^4} - {(2x)^5}
= 1 - 10x + 40x² - 80x³ + 80x^4 - 32x^5
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