Question

using binomial theorem find the value of (1.1)^10​

Answer 1

Answer:

(i)(102)

4

=(100+2)

4

=

4

C

0

(100)

4

+

4

C

1

(100)

3

(2)+

4

C

2

(100)

2

2

2

+

4

C

3

(100)(2)

3

+

4

C

2

(2)

4

=(100)

4

+4.(100)

3

2+6(100)

2

2

2

+4(100)2

3

+2

3

100000000+8000000+240000+3200+16

=108243216

(ii)(1+0.1)

5

=

5

C

0

1

5

+

5

C

1

1

4

(0.1)+

2

C

2

1

3

(0.1)

2

+

5

C

3

1

2

(0.1)

3

+

5

C

4

1(0.1)

4

+

5

C

5

(0.1)

5

=1+5(0.1)+10(0.1)

2

+10(0.1)

3

+5(0.1)

4

+(0.1)

5

=1+0.5+0.1+0.01+0.0005+0.00001

=1.61051